arg1 -le arg2 (conditional operator)

true if integer arg1 is less than or equal to integer arg2.

Examples

Different ways to compare two integers:
1
2
3
4
test "$n" -le 42 && echo "$n <= 42"
[ "$n" -le 42 ] && echo "$n <= 42"
# Bash
[[ "$n" -le 42 ]] && echo "$n <= 42"
BashSupport Pro 是一个 支持 -le 的 Bash 集成开发工具 – 马上试用
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