arg1 -le arg2 (conditional operator)
true if integer arg1 is less than or equal to integer arg2.
Links
Examples
- Different ways to compare two integers:
1 2 3 4test "$n" -le 42 && echo "$n <= 42" [ "$n" -le 42 ] && echo "$n <= 42" # Bash [[ "$n" -le 42 ]] && echo "$n <= 42"
BashSupport Pro 是一个 支持 -le 的 Bash 集成开发工具 – 马上试用!